The number of moles of `K_(2)Cr_(2)O_(7)` reduced by one mole of `Sn^(2+)` ions is

Options

A. `(1)/(3)`
B. `(1)/(6)`
C. `(2)/(3)`
D. `1`

Answer

A

Explanation

`Cr_(2)O_(7)^(2-)=Sn^(2+)(Sn^(2+)toSn^(4+)+2e^(-))`
`(n=6)(n=2)`
`1Eq=1Eq`
`(1)/(6)mol=(1)/(2)mol`
`therefore1 " mol of "Sn^(2+)=(2)/(6) " mol of "Cr_(2)O_(7)^(2-)`
`(1)/(3) " mol of "Cr_(2)O_(7)^(2-)`