Home
Class 11
CHEMISTRY
(a). IF both (A) and (R) are correct and...

(a). IF both (A) and (R) are correct and (R) is the correct explanation of (A).
(b). If both (A) and (R) are correct but (R) is not the correct explanation of (A).
(c). If (A) is correct, but (R) is incorrect.
(d). If (A) is incorrect, but (R) is correct. ltbr. (e) if both (A) and (R) are incorrect.
Q. Assertion (A): In the titration of strong acid and strong base, phenolphthalein is used as suitable indocator.
Reason (R): IN the titration of strong acid and strong base, the equivalence points lies is the pH range of `(3.0-10.5)` and phenolphthalein have pH range of `(8.0-9.8)`.

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question, we need to analyze the assertion (A) and the reason (R) given in the problem: **Assertion (A):** In the titration of strong acid and strong base, phenolphthalein is used as a suitable indicator. **Reason (R):** In the titration of strong acid and strong base, the equivalence point lies in the pH range of (3.0-10.5) and phenolphthalein has a pH range of (8.0-9.8). ### Step-by-Step Solution: 1. **Understanding the Assertion (A):** - Phenolphthalein is indeed a suitable indicator for titrations involving strong acids and strong bases. It changes color in the pH range of approximately 8.0 to 9.8, which is appropriate for detecting the endpoint of such titrations. **Hint:** Recall the pH range of phenolphthalein and its function as an indicator. 2. **Understanding the Reason (R):** - The equivalence point in a titration of a strong acid with a strong base typically occurs around pH 7. However, the reason states that the equivalence point lies between pH 3.0 and 10.5. This range is indeed correct, as it encompasses the pH at which neutralization occurs (around pH 7) and the pH values that can be observed during the titration. **Hint:** Consider the nature of strong acid-strong base reactions and their equivalence points. 3. **Evaluating the Relationship Between (A) and (R):** - Both the assertion and the reason are correct statements. The assertion correctly identifies phenolphthalein as a suitable indicator, and the reason correctly describes the pH range of the equivalence point for the titration of strong acids and strong bases. **Hint:** Determine if the reason provides a valid explanation for the assertion. 4. **Conclusion:** - Since both (A) and (R) are correct and (R) provides the correct explanation for (A), the correct answer is: - **(a)** If both (A) and (R) are correct and (R) is the correct explanation of (A). ### Final Answer: (a) If both (A) and (R) are correct and (R) is the correct explanation of (A). ---

To solve the question, we need to analyze the assertion (A) and the reason (R) given in the problem: **Assertion (A):** In the titration of strong acid and strong base, phenolphthalein is used as a suitable indicator. **Reason (R):** In the titration of strong acid and strong base, the equivalence point lies in the pH range of (3.0-10.5) and phenolphthalein has a pH range of (8.0-9.8). ### Step-by-Step Solution: ...
Promotional Banner

Topper's Solved these Questions

  • STOICHIOMETRY

    CENGAGE CHEMISTRY ENGLISH|Exercise Exercises Integer|16 Videos
  • STOICHIOMETRY

    CENGAGE CHEMISTRY ENGLISH|Exercise Archives Multiple Correct|1 Videos
  • STOICHIOMETRY

    CENGAGE CHEMISTRY ENGLISH|Exercise Exercises Single Correct|85 Videos
  • STATES OF MATTER

    CENGAGE CHEMISTRY ENGLISH|Exercise Exercises (Ture False)|25 Videos
  • THERMODYNAMICS

    CENGAGE CHEMISTRY ENGLISH|Exercise Archives (Subjective)|23 Videos

Similar Questions

Explore conceptually related problems

(a). IF both (A) and (R) are correct and (R) is the correct explanation of (A). (b). If both (A) and (R) are correct but (R) is not the correct explanation of (A). (c). If (A) is correct, but (R) is incorrect. (d). If (A) is incorrect, but (R) is correct. ltbr. (e) if both (A) and (R) are incorrect. Q. Assertion (A): H_(3)PO_(2) is mono basic acid. Reason (R): Two H-atoms are attached to pghosphorous (P).

(a). IF both (A) and (R) are correct and (R) is the correct explanation of (A). (b). If both (A) and (R) are correct but (R) is not the correct explanation of (A). (c). If (A) is correct, but (R) is incorrect. (d). If (A) is incorrect, but (R) is correct. ltbr. (e) if both (A) and (R) are incorrect. Q. Assertion (A): Concentration of H_(2)O_(2) is expressed in volume Reason (R): Volume strength = normality xx5.6

(a). IF both (A) and (R) are correct and (R) is the correct explanation of (A). (b). If both (A) and (R) are correct but (R) is not the correct explanation of (A). (c). If (A) is correct, but (R) is incorrect. (d). If (A) is incorrect, but (R) is correct. ltbr. (e) if both (A) and (R) are incorrect. Q. Assertion (A): IN the reaction i_(2) is a oxidant. 2S_(2)O_(3)^(2-)+I_(2)toS_(4)O_(6)^(2-)+2I^(ɵ) Reason (R): During oxidation loss of electron takes place.

(a). If both (A) and (R) are correct and (R) is the correct explanation for (A). (b). If both (A) and (R) are correct and (R) is the correct explanation for (A). (c). If (A) is correct and (R) is incorrect. (d). If (A) is incorrect and (R) is correct. ltbr. (e). If both (A) and (R) are incorrect. Q. Assertion (A): Essential oils are volatile and are isoluble in H_2O Reason (R): Essential oils are purified by steam ditillation.

(a). IF both (A) and (R) are correct and (R) is the correct explanation of (A). (b). If both (A) and (R) are correct but (R) is not the correct explanation of (A). (c). If (A) is correct, but (R) is incorrect. (d). If (A) is incorrect, but (R) is correct. ltbr. (e) if both (A) and (R) are incorrect. Q. Assertion: 5.0 " mol of "ferrous oxalate are completely oxidised by 2.5 moles of acidic solution of K_(2)Cr_(2)O_(7) . Reason(R): n-factor of ferrous oxalate against dichromate is 3.

(a). IF both (A) and (R) are correct and (R) is the correct explanation of (A). (b). If both (A) and (R) are correct but (R) is not the correct explanation of (A). (c). If (A) is correct, but (R) is incorrect. (d). If (A) is incorrect, but (R) is correct. ltbr. (e) if both (A) and (R) are incorrect. Q. Assertion (A): Equivalent mass of KMnO_(4) is equal to one-fifth of its molecular mass when it acts as oxidising agent in mild basic medium. Reason (R): Oxidation number of Mn in KMnO_(4) is +7 .

(a). IF both (A) and (R) are correct and (R) is the correct explanation of (A). (b). If both (A) and (R) are correct but (R) is not the correct explanation of (A). (c). If (A) is correct, but (R) is incorrect. (d). If (A) is incorrect, but (R) is correct. ltbr. (e) if both (A) and (R) are incorrect. Q. Assertion (A): Estimation of reducing substance by the use of standard I_(2) is called iodometry. Reason (R): in the reaction I_(2)+S_(2)O_(3)^(2-)toS_(4)O_(6)^(2-)+2I^(ɵ) The n factor of S_(2)O_(3)^(2-) is one.

(a). IF both (A) and (R) are correct and (R) is the correct explanation of (A). (b). If both (A) and (R) are correct but (R) is not the correct explanation of (A). (c). If (A) is correct, but (R) is incorrect. (d). If (A) is incorrect, but (R) is correct. ltbr. (e) if both (A) and (R) are incorrect. Q. Assertion (A): When gaseous hydrocarbon are completely burnt in eudiometer tube with excess of O_(2) and after cooling there is a contraction in the volume of gases. Reason (R): The volume of H_(2)O is not considered.

(a). IF both (A) and (R) are correct and (R) is the correct explanation of (A). (b). If both (A) and (R) are correct but (R) is not the correct explanation of (A). (c). If (A) is correct, but (R) is incorrect. (d). If (A) is incorrect, but (R) is correct. ltbr. (e) if both (A) and (R) are incorrect. Q. Assertion (A): MnO_(4)^(ɵ)+S_(2)O_(3)^(2-)underset(pH=7)toMnO_(2)+HSO_(4)^(ɵ) Reason (R): The n factor for MnO_(4)^(ɵ) and S_(2)O_(3)^(2-) ions respectively are 3 and 8.

(a). If both (A) and (R) are correct and (R) is the correct explanation for (A). (b). If both (A) and (R) are correct and (R) is not the correct explanation for (A). (c). If (A) is correct and (R) is incorrect. (d). If (A) is incorrect and (R) is correct.(e). If both (A) and (R) are incorrect. Q. Assertion (A): Hydroxylamine (NH_2OH) contains N, and hence gives prussian blue colour in lassaigne's test. Reason (R): Hydroxylamine does not contain C, so with Na metal. CN^(-) ion is not formed.