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From the alpha - particle scattering exp...

From the alpha - particle scattering experiment Rutherford concluded that

A

`alpha`- particle can come within a distance of the order of `10^(-14) m ` of the nucleus

B

The radius of the nucleus is less than `10^(-14) m `

C

Scattering follows coulomb's law

D

The positively charged parts of the atom move with extremely high velocities

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**Step-by-Step Solution:** 1. **Understanding the Experiment**: The alpha-particle scattering experiment, conducted by Ernest Rutherford, involved firing alpha particles at a thin gold foil. The behavior of these particles when they encountered the foil provided insights into the structure of the atom. 2. **Analyzing the Options**: - **Option A**: "Alpha particles can come within the distance of the order of 10^-4 m from the nucleus." - This statement is **false**. Alpha particles do not penetrate close to the nucleus; they are repelled by the positively charged nucleus, indicating that most of the atom is empty space. - **Option B**: "The radius of the nucleus is less than 10^-14 m." - This statement is **true**. Rutherford's calculations indicated that the nucleus is indeed on the order of 10^-14 to 10^-15 meters in radius, based on the scattering patterns of the alpha particles. - **Option C**: "Scattering follows Coulomb's law." - This statement is **partially true** but misleading in this context. While the forces involved in the scattering can be described by Coulomb's law, the primary goal of the experiment was not to demonstrate this law. - **Option D**: "The positively charged parts of the atom move with extremely high velocities." - This statement is **false**. The positively charged particles (protons) reside in the nucleus and do not move around like electrons do. The electrons are the ones that orbit around the nucleus. 3. **Conclusion**: Based on the analysis of the options, the correct conclusion from Rutherford's alpha-particle scattering experiment is that **the radius of the nucleus is less than 10^-14 m (Option B)**. ---
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CENGAGE CHEMISTRY ENGLISH-ATOMIC STRUCTURE-Concept Applicationexercise(4.3)
  1. From the alpha - particle scattering experiment Rutherford concluded ...

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  2. How many quantum number are needed in designate an orbital ? Name the...

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  3. The principal quantum number of n of an atomic orbitals is 5 what are ...

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  4. (a) An atomic orbital has n=3. What are the possible values of l? (b...

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  5. What is the lowest value of n that allows g orbital to exist?

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  6. Given the notation for the sub-shell deotected by the following quant...

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  7. How many electron on a fully filled f sub-shell have m(1) = 0 ?

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  8. An electron is in one of the 3d orbitals. Give the possible values of ...

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  9. If the largest value ofm(1) for an electron is + 3 in what type of su...

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  10. Explain giving reasons, which of the following sets of quantum numbers...

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  11. How many electron in atom may have the following quantum number ? A n ...

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  12. How many orbitals are possible in a. 4th energy level b. 5f sub-she...

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  13. What are the possible values of l and m(1) for an atomic orbital 4f?

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  14. What is the shape of 1s and 2s orbital .Give two point of difference ...

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  15. (a) How many sub-shells are associated with n = 4? (b) How many electr...

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  16. How many spherical nodes are present in 4s orbital in a hydrogen ato...

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  17. The principal quantum number representwsw

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  18. The energy of an electron of 2p(1) orbital is

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  19. The orbital angular momentum of an electron of an electron in 2s orbit...

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  20. The number of angular nodal planes of zero electron density in the d(...

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