Naturally occurring boron consists of two isotopes whose atomic weight are `10.01` and `11.01`The atomic weight of natural boron is `10.81` Calculate the percentage of each isotope in natural boron

Explanation

To solve the problem of determining the percentage of each isotope of boron in naturally occurring boron, we can follow these steps:

### Step 1: Define Variables
Let:
- \( x \) = percentage of the isotope with atomic weight 10.01
- \( 100 - x \) = percentage of the isotope with atomic weight 11.01

### Step 2: Set Up the Equation for Average Atomic Mass
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