Calculate the density of fluorine nucleus supposing that the shape of the nucleus is spherical and its radius is `5 xx 10^(-13)` (Mass of `f =19` ams)

Explanation

Mass of the nucleus of F atom `= 19 + 1.66 xx 10^(24)g (1 "amu" = 1.660 xx 10^(-24) g)` Volume of the nucleus of F atom `= (4)/(3) pi r^(3)`
`= (4)/(3) xx 3.14 (5 xx 10^(-13))^(3) = 525 xx 10^(-39) cm^(3)`
Density of the neucleus of F atom = `("Mass" )/("Volume") = (10 xx 1.66 xx 10^(24)g)/(525 xx 10^(-29) cm^(3)) = 6.0 xx 10^(13) g cm^(3)`