In a photoelectric effect experiment irradiation of a metal with light of frequency `5.2 xx 10^(14) s^(-1)` yields elctrons with maximum kinetic ennergy `1.3 xx 10^(-19) J`.Calculate the threshold frequency `(v_(0))` for the metal

Explanation

To find the threshold frequency \( v_0 \) for the metal in a photoelectric effect experiment, we can use the equation derived from the photoelectric effect:

\[ h\nu = h\nu_0 + KE \]

Where:
- \( h \) is Planck's constant (\( 6.626 \times 10^{-34} \, \text{Js} \))
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