With what velocity should an `alpha`- particle travel towards the nucleus of a copper atom at a distance of `10^(-13)m` from the nucleus of the copper atom?

Explanation

To find the velocity with which an alpha particle should travel towards the nucleus of a copper atom at a distance of \(10^{-13} \, m\), we need to equate the potential energy experienced by the alpha particle due to the copper nucleus with its kinetic energy.

### Step-by-Step Solution:

1. **Identify the Charges**:
- An alpha particle consists of 2 protons, so its charge \(q_1\) is:
\[
q_1 = 2 \times e = 2 \times 1.6 \times 10^{-19} \, C = 3.2 \times 10^{-19} \, C
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