For silver metal `mu_(0)` is `1.13 xx 10^(17)s^(-1)` .What is the maximum energy of the photoelectron produced by shining uatraviolet light wavelength `1.5` nm on the metal?

Explanation

To solve the problem of finding the maximum energy of the photoelectron produced by shining ultraviolet light on silver metal, we can follow these steps:

### Step 1: Convert the wavelength to meters
The given wavelength of the ultraviolet light is 1.5 nm. We need to convert this to meters for our calculations.

\[ \lambda = 1.5 \, \text{nm} = 1.5 \times 10^{-9} \, \text{m} \]
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