What will be the kinetic energy and total energy of an electron in H atom if the atom emit a photon of wavelength `4860 Å` ?

Explanation

To find the kinetic energy and total energy of an electron in a hydrogen atom when a photon of wavelength 4860 Å is emitted, we can follow these steps:

### Step 1: Convert Wavelength to Meters
The wavelength given is in angstroms. We need to convert it to meters for our calculations.

\[ \text{Wavelength} (\lambda) = 4860 \, \text{Å} = 4860 \times 10^{-10} \, \text{m} \]
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