A hydrogen atom in the ground state is hit by a photon exctting electron to the thoird excerd state .The electron then drops to the second orbit. What is the frequency of radiation emitted and abserbed in the process ?

Explanation

To solve the problem step-by-step, we will calculate the frequency of radiation absorbed and emitted by the hydrogen atom during the transitions of the electron.

### Step 1: Identify the Energy Levels
The hydrogen atom in the ground state has an electron in the first energy level (n=1). When it is hit by a photon, it gets excited to the third excited state, which corresponds to n=4 (since the first excited state is n=2, the second is n=3, and the third is n=4).

### Step 2: Calculate the Energy Absorbed
The energy difference (ΔE) when the electron transitions from n=1 to n=4 can be calculated using the formula:
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