Ratio of frequency of revolution of electron in the second state of `He^(o+)` revolution of electron in the second state `He^(Theta)` and second state of hydrogen is

Options

A. `(32)/(27)`
B. `(27)/(32)`
C. `(1)/(34)`
D. `(27)/(2)`

Explanation

To solve the problem of finding the ratio of the frequency of revolution of an electron in the second state of `He^(o+)`, `He^(Theta)`, and the second state of hydrogen, we can follow these steps:

### Step 1: Understand the relationship between frequency, time period, and velocity
The frequency of revolution (μ) of an electron can be expressed as:
\[ \mu = \frac{1}{T} \]
where \( T \) is the time period of revolution. The time period can be expressed in terms of the radius \( R \) and velocity \( V \):
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