An electron in the third energy level of an excited `He^(o+)` ion return back to the ground sate .The photon emitted in the process is absorbed by a stationary hydrogen atom in the process is absermine by a stationary hydrogen atom in the ground state .Determine the velocity of the photoelectron ejected from the hydrogen atom in metre per second

Explanation

To solve the problem, we need to follow these steps:

### Step 1: Determine the energy released by the transition in the He⁺ ion
The transition occurs from the third energy level (n=3) to the ground state (n=1) for the He⁺ ion. The energy of an electron in a hydrogen-like atom can be calculated using the formula:

\[ E_n = -\frac{13.6 \, Z^2}{n^2} \, \text{eV} \]
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