The circumference of the second Bohr orbit of electron in the hydrogen atom is 600nm. Calculate the potential difference to which the electron has to be subjected so that the electron stops. The electron had the de Broglie wavelength corresponding to the circumference.

Explanation

To solve the problem step by step, we will follow the reasoning provided in the video transcript.

### Step 1: Understand the relationship between the circumference and the de Broglie wavelength
The circumference of the second Bohr orbit is given as 600 nm. The de Broglie wavelength (λ) of the electron corresponds to this circumference. The number of wavelengths fitting into the circumference is given by:

\[ n \lambda = \text{Circumference} \]
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