Home
Class 11
CHEMISTRY
The number of waves in the fourth bohr o...

The number of waves in the fourth bohr orbit of hydrogen is

A

3

B

4

C

9

D

12

Text Solution

AI Generated Solution

The correct Answer is:
To find the number of waves in the fourth Bohr orbit of hydrogen, we can follow these steps: ### Step 1: Understand the relationship between the circumference of the orbit and the wavelength The electron in the Bohr orbit travels in a circular path, and the distance it travels in one complete revolution is equal to the circumference of the orbit. The circumference \( C \) of the orbit is given by: \[ C = 2\pi r \] where \( r \) is the radius of the orbit. ### Step 2: Relate the circumference to the wavelength and number of waves The number of waves \( n \) in the orbit can be expressed as: \[ C = n \cdot \lambda \] where \( \lambda \) is the wavelength of the electron. ### Step 3: Substitute the expression for wavelength According to de Broglie's hypothesis, the wavelength \( \lambda \) of the electron can be expressed as: \[ \lambda = \frac{h}{mv} \] where \( h \) is Planck's constant, \( m \) is the mass of the electron, and \( v \) is its velocity. ### Step 4: Combine the equations Substituting the expression for \( \lambda \) into the circumference equation gives us: \[ 2\pi r = n \cdot \frac{h}{mv} \] ### Step 5: Rearranging the equation to find \( n \) Rearranging the above equation to solve for \( n \): \[ n = \frac{2\pi r mv}{h} \] ### Step 6: Use the angular momentum quantization condition According to Bohr's model, the angular momentum \( L \) of the electron in the nth orbit is quantized and given by: \[ L = mv r = n \cdot \frac{h}{2\pi} \] For the fourth orbit (\( n = 4 \)): \[ mv r = 4 \cdot \frac{h}{2\pi} \] ### Step 7: Substitute the angular momentum into the equation for \( n \) Now substituting \( mv r \) into the equation for \( n \): \[ n = \frac{2\pi r \cdot \left(4 \cdot \frac{h}{2\pi}\right)}{h} \] ### Step 8: Simplifying the expression This simplifies to: \[ n = \frac{2\pi r \cdot 4 \cdot \frac{h}{2\pi}}{h} = 4 \] ### Conclusion Thus, the number of waves in the fourth Bohr orbit of hydrogen is: \[ \boxed{4} \]

To find the number of waves in the fourth Bohr orbit of hydrogen, we can follow these steps: ### Step 1: Understand the relationship between the circumference of the orbit and the wavelength The electron in the Bohr orbit travels in a circular path, and the distance it travels in one complete revolution is equal to the circumference of the orbit. The circumference \( C \) of the orbit is given by: \[ C = 2\pi r \] where \( r \) is the radius of the orbit. ...
Promotional Banner

Topper's Solved these Questions

  • ATOMIC STRUCTURE

    CENGAGE CHEMISTRY ENGLISH|Exercise Exercises (Subjective)|52 Videos
  • ATOMIC STRUCTURE

    CENGAGE CHEMISTRY ENGLISH|Exercise Exercises Linked Comprehension|50 Videos
  • APPENDIX - INORGANIC VOLUME 1

    CENGAGE CHEMISTRY ENGLISH|Exercise chapter-7 Single correct answer|1 Videos
  • CHEMICAL BONDING AND MOLECULAR STRUCTURE

    CENGAGE CHEMISTRY ENGLISH|Exercise Archives Subjective|15 Videos

Similar Questions

Explore conceptually related problems

The circumference of the 4^(th) bohr orbit of hydrogen is 5.32 nm .The wavelenght of electron revolving in the first bohr orbit will be

The number of waves in n^("th") orbit are:

If the de Broglie wave length of the fourth Bohr's orbit of hydrogen atom is 4 Å, the circumference of the orbit is:

If the speed of electron in the first bohr orbit of hydrogen atom is x then the speed of the electron in the third Bohr orbit of hydrogen is

If the speed of electron in the first bohr orbit of hydrogen atom is x then the speed of the electron in the third Bohr orbit of hydrogen is

Calculate angular momentum of an electron in the third Bohr orbit of hydrogen atom.

The velocity of an electron in the first Bohr orbit of hydrogen atom is 2.19 xx 10^(6)ms^(-1) . Its velocity in the second orbit would be

The value of orbit angular momentum of an electron in the 3^(rd) Bohr orbit of hydrogen will be

The number of revolutions per second made by an electron in the first Bohr orbit of hydrogen atom is of the order of 3 :

The radius of the first Bohr orbit of hydrogen atom is 0.529Å . The radius of the third orbit of H will be:

CENGAGE CHEMISTRY ENGLISH-ATOMIC STRUCTURE-Concept Applicationexercise(4.3)
  1. The number of waves in the fourth bohr orbit of hydrogen is

    Text Solution

    |

  2. How many quantum number are needed in designate an orbital ? Name the...

    Text Solution

    |

  3. The principal quantum number of n of an atomic orbitals is 5 what are ...

    Text Solution

    |

  4. (a) An atomic orbital has n=3. What are the possible values of l? (b...

    Text Solution

    |

  5. What is the lowest value of n that allows g orbital to exist?

    Text Solution

    |

  6. Given the notation for the sub-shell deotected by the following quant...

    Text Solution

    |

  7. How many electron on a fully filled f sub-shell have m(1) = 0 ?

    Text Solution

    |

  8. An electron is in one of the 3d orbitals. Give the possible values of ...

    Text Solution

    |

  9. If the largest value ofm(1) for an electron is + 3 in what type of su...

    Text Solution

    |

  10. Explain giving reasons, which of the following sets of quantum numbers...

    Text Solution

    |

  11. How many electron in atom may have the following quantum number ? A n ...

    Text Solution

    |

  12. How many orbitals are possible in a. 4th energy level b. 5f sub-she...

    Text Solution

    |

  13. What are the possible values of l and m(1) for an atomic orbital 4f?

    Text Solution

    |

  14. What is the shape of 1s and 2s orbital .Give two point of difference ...

    Text Solution

    |

  15. (a) How many sub-shells are associated with n = 4? (b) How many electr...

    Text Solution

    |

  16. How many spherical nodes are present in 4s orbital in a hydrogen ato...

    Text Solution

    |

  17. The principal quantum number representwsw

    Text Solution

    |

  18. The energy of an electron of 2p(1) orbital is

    Text Solution

    |

  19. The orbital angular momentum of an electron of an electron in 2s orbit...

    Text Solution

    |

  20. The number of angular nodal planes of zero electron density in the d(...

    Text Solution

    |