The kinetic energy of an electron in H like atom is `6.04 eV` Find the area of the third bohr orbit to which this electron belongs .Also report the atom

Explanation

To solve the problem step by step, we will follow the outlined process to find the area of the third Bohr orbit and identify the atom.

### Step 1: Convert Kinetic Energy from eV to Joules
The kinetic energy (KE) of the electron is given as 6.04 eV. To convert this to joules, we use the conversion factor \(1 \text{ eV} = 1.6 \times 10^{-19} \text{ J}\).

\[ KE = 6.04 \, \text{eV} \times 1.6 \times 10^{-19} \, \text{J/eV} = 9.664 \times 10^{-19} \, \text{J} \]
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