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The energy of an electron in the first B...

The energy of an electron in the first Bohr orbit of H atom is `-13.6 eV` The possible energy value (s) of excited state(s) for the electron in the Bohr orbit of hydrogen is//are

A

`-3.4 eV`

B

`-4.2 eV`

C

`6.8 eV`

D

`+6.8 eV`

Text Solution

Verified by Experts

`E_(n) = (-13.6)/(n^(2))eV`
when `n =2,E_(2) =(-13.6)/(4) = 3.4 eV`
Hence (a) is the correct answer
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