Find out the energy of H atom in the first excitation state .The value of permittivity factor `4pi epsilon_(n) = 1.11264 xx 10^(-10) C^(2)N^(-1)m^(-1)`

Explanation

To find the energy of the hydrogen atom in the first excitation state, we can use the formula for the energy of an electron in the nth state of a hydrogen atom:

\[ E_n = -\frac{2 \pi^2 Z^2 m_e e^4}{(4 \pi \epsilon_0) n^2 h^2} \]

Where:
- \(E_n\) is the energy of the electron in the nth state,
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