Home
Class 11
CHEMISTRY
The probability of fiating the electr...

The probability of fiating the electron in `p_(s)` orbits is :

A

maximum on two apposite side of the nucless along x-axis

B

zero at the nucless

C

same on all the sides around the nucless

D

zero on the x-axis

Text Solution

Verified by Experts

For `p_(s)` nodel plate cojntaints x-asxis No elctron on lie at nucles `p_(2)`gives for produbility of finding electron along x-rays and it will be maximum
Promotional Banner

Topper's Solved these Questions

  • ATOMIC STRUCTURE

    CENGAGE CHEMISTRY ENGLISH|Exercise Exercises (Subjective)|52 Videos
  • ATOMIC STRUCTURE

    CENGAGE CHEMISTRY ENGLISH|Exercise Exercises Linked Comprehension|50 Videos
  • APPENDIX - INORGANIC VOLUME 1

    CENGAGE CHEMISTRY ENGLISH|Exercise chapter-7 Single correct answer|1 Videos
  • CHEMICAL BONDING AND MOLECULAR STRUCTURE

    CENGAGE CHEMISTRY ENGLISH|Exercise Archives Subjective|15 Videos

Similar Questions

Explore conceptually related problems

Which of the following statements is wrong? The probability of finding the electron in p_(x) orbital is

The probability of finding the electron in p_(x) orbit is :

The probability of finding an electron in p_(y) orbital along the x-axis is

The probability of finding electron in d_(xy) orbital is :

The maximum probability of finding electron in the d_(xy) orbital is -

Orbitals are the pictorial representationof Psi or Psi ^(2) Psi^(2) tell about the probability of finding electron. A 2p_(x) orbital is shown by given diagram Correct regarding diagram is

Out of the following, which is the correct match for the radial probability of finding the electron for 2s orbital

In which of the following pairs is the probability of finding the electron in only xy - plane is zero for both orbitals ?

In which of the following case would be probability of finding an electron residing in a d_(xy) orbital be zero ?

Which of the following orbitals will have zero probability of finding the electron in the yz plane

CENGAGE CHEMISTRY ENGLISH-ATOMIC STRUCTURE-Concept Applicationexercise(4.3)
  1. The probability of fiating the electron in p(s) orbits is :

    Text Solution

    |

  2. How many quantum number are needed in designate an orbital ? Name the...

    Text Solution

    |

  3. The principal quantum number of n of an atomic orbitals is 5 what are ...

    Text Solution

    |

  4. (a) An atomic orbital has n=3. What are the possible values of l? (b...

    Text Solution

    |

  5. What is the lowest value of n that allows g orbital to exist?

    Text Solution

    |

  6. Given the notation for the sub-shell deotected by the following quant...

    Text Solution

    |

  7. How many electron on a fully filled f sub-shell have m(1) = 0 ?

    Text Solution

    |

  8. An electron is in one of the 3d orbitals. Give the possible values of ...

    Text Solution

    |

  9. If the largest value ofm(1) for an electron is + 3 in what type of su...

    Text Solution

    |

  10. Explain giving reasons, which of the following sets of quantum numbers...

    Text Solution

    |

  11. How many electron in atom may have the following quantum number ? A n ...

    Text Solution

    |

  12. How many orbitals are possible in a. 4th energy level b. 5f sub-she...

    Text Solution

    |

  13. What are the possible values of l and m(1) for an atomic orbital 4f?

    Text Solution

    |

  14. What is the shape of 1s and 2s orbital .Give two point of difference ...

    Text Solution

    |

  15. (a) How many sub-shells are associated with n = 4? (b) How many electr...

    Text Solution

    |

  16. How many spherical nodes are present in 4s orbital in a hydrogen ato...

    Text Solution

    |

  17. The principal quantum number representwsw

    Text Solution

    |

  18. The energy of an electron of 2p(1) orbital is

    Text Solution

    |

  19. The orbital angular momentum of an electron of an electron in 2s orbit...

    Text Solution

    |

  20. The number of angular nodal planes of zero electron density in the d(...

    Text Solution

    |