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The quantum number of electrons are give...

The quantum number of electrons are given below: Arrange then in order of increasing energies
a.`n= 4,l= 2,m_(1)= -2, m_(s)= -(1)/(2)`
b.`n= 3,l= 2,m_(1) = 1, m_(s)= +(1)/(2)`
c.`n= 4,l= 1,m_(1) = 0, m_(s)= +(1)/(2)`
`e.n= 3,l= 2,m_(1)= -2, m_(s)= +(1)/(2)`
f.`n= 4,l= 1,m_(1) = +1, m_(s)= +(1)/(2)`

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To arrange the given quantum numbers in order of increasing energies, we will follow these steps: ### Step 1: Identify the orbitals based on the quantum numbers The quantum numbers provided are: - a. \( n= 4, l= 2 \) (4D) - b. \( n= 3, l= 2 \) (3D) - c. \( n= 4, l= 1 \) (4P) - d. \( n= 3, l= 2 \) (3D) ...
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The quantum numbers of six electrons are given below. Arrange them in order of increasing energies. If any of these combination(s) has/have the same energy lists: 1. n=4 , l=2 , m_(i) =-2, m_(s) =-1//2 2. n=3 , l=2 , m_(l) =1 , m_(s) =+1//2 3. n=4 , l=2 ,m_(l)=-2, m_(s) =-1//2 4. n=3 , l= 2, m_(i) =-1 , m_(s) = +1//2 5. n=3 , l=1 , m_(l) =-1 , m_(s) = +1//2 6. n=4 , l= 1 , m_(l) =0 , m_(s) =+1//2

Explain , giving reason , which of the following sets of quantum number are not possible {:(a,n= 0 ,l = 0, m_(1) = 0, m_(s) = +1//2),(b,n= 1 ,l = 0, m_(1) = 0, m_(s) = -1//2),(c,n= 1 ,l = 1, m_(1) = 0, m_(s) = +1//2),(d,n= 2 ,l = 1, m_(1) = 0, m_(s) = -1//2),(e,n= 3 ,l = 3, m_(1) = -3, m_(s) = +1//2),(f,n= 3 ,l = 1, m_(1) = 0, m_(s) = +1//2):}

State which of the following sets of quantum number would be possible and which would not be permisible for an electron in an atom. (i) n=3,I=3,m_(l)=+3, m_(s)=+(1)/(2) (ii) n=3,I=3,m_(l)=+1, m_(s)=-(1)/(2) (iii) n=5,I=4,m_(l)=+3, m_(s)=(1) (iv) n=0,I=0,m_(l)=0, m_(s)=+(1)/(2) (v) n=4,I=3,m_(l)=-2, m_(s)=-(1)/(2)

The quantum number of four electrons are given below: n=4,l=2,m_(l)=-2,m_(s)=-1//2 n=3,l=2,m_(l),m_(s)=+1//2 n=4,l=1,m_(l)=0,m_(s)=+1//2 n=3,l=1,m_(l)=1,m_(s)=-1//2 The correct order of their increasing energies will be:

Explain giving reasons, which of the following sets of quantum numbers are not possible? (a) n=0, l=0, m_(l)=0, m_(s)=+1/2 (b) n=1, l=0, m_(l)=0, m_(s)=-1/2 (c) n=1, l=1, m_(l)=0, m_(s)=+1/2 (d) n=2, l=1, m_(l)=0, m_(s)=-1/2 (e) n=3, l=3, m_(l)=-3, m_(s)=+1/2 (f) n=3, l=1, m_(l)=0, m_(s)=+1/2

Arrange the electrons represented by the following sets of quantum numbers in decreasing order of energy. (i) n=4, l=0, m_(l)=0, s=+1//2 , (ii) n=3, l=1, m_(l)=1, s=-1//2 (iii) n=3, l=2, m_(l)=0, s=+1//2 , (iv) n=3, l=0, m_(l)=0, s=-1//2

From the following sets of quantum numbers , state which are possible ? (i) n=0,l=0,m_(l)=1,m_(s)= +1//2 (ii) n=2,l=1,m_(l)=0,m_(s) = -1//2 (iii) n=2, l=0,m_(1)=3,m_(s) = +1//2 (iv) n=3,l=1,m_(l)=0,m_(s) = +1//2

From the following sets quantum number state which are possible. Explain why the other are not permitted ? a. n = 0, l = 0, m= 0, s = + 1//2 b. n = 1, l = 0, m= 0, s = - 1//2 c. n = 1, l = 1, m= 0, s = + 1//2 d. n = 1, l = 0, m= +1, s = + 1//2 e. n = 0, l = 1, m= -1, s = - 1//2 f. n = 2, l = 2, m= 0, s = - 1//2 g. n = 2, l = 1, m= 0, s = - 1//2

The decrerasing order of energy for the electrons represented by the following sets of quantum number is : 1. n = 4,l = 0,m = 0,s = +- 1//2 2. n = 3,l = 1,m = 1,s = - 1//2 3. n = 3,l = 2,m = 0,s = + 1//2 4. n = 3,l = 0,m = 0,s = - 1//2

The quantum number of four electrons are given below: I. n=4,l=2,m_l=-2,m_s=-1/2 II. n=3,l=2,m_l=1,m_s=+1/2 III. n = 4 , l =1 ,m _l=0 ,m_s=+1/2 IV. n=3,l=1,m_l=1,m_s=-1/2 The correct order of their increasing energies will be

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