Supposing that the pauli exclusion principal is not correct orbital can accammodate three electrons when are the respective atomic number of the second number of alkali metal and the first number of halogen family ?

Options

A. `16,14`
B. `11,9`
C. `16,9`
D. `34,17`

Explanation

To solve the question, we need to find the atomic numbers of the second alkali metal and the first halogen family member, assuming that the Pauli Exclusion Principle does not hold and that each orbital can accommodate three electrons instead of two.

### Step-by-Step Solution:

1. **Identify the Second Alkali Metal:**
- The alkali metals are located in Group 1 of the periodic table. The first two alkali metals are lithium (Li) with atomic number 3 and sodium (Na) with atomic number 11. Therefore, the second alkali metal is sodium (Na).

2. **Determine the Electron Configuration of Sodium:**
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