What will be the atomic number of an atom if its electronic configuration is `(n - 2)s^(2) (n - 1)s^(a) p^(b) ns^(2)p^(2)` where `n = 3, a= 2` and `b= 6` ?

Explanation

To find the atomic number of an atom given its electronic configuration, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the given values**:
- The electronic configuration is given as `(n - 2)s^2 (n - 1)s^a p^b ns^2 p^2`.
- We have `n = 3`, `a = 2`, and `b = 6`.

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