The wave function orbital of H-like atoms is given as order
`psi_(2s) = (1)/(4sqrt(2pi)) Z^(3//2) (2 - Zr)e^(Zr//2)`
Given that the radius is in `Å` then which of the following is the radius for nodal surface for `He^(Theta)` ion ?

Options

A. `1Å`
B. `2 Å`
C. `2.5 Å`
D. `4 Å`

Explanation

To find the radius for the nodal surface for the He⁺ ion using the given wave function orbital for H-like atoms, we can follow these steps:

### Step 1: Understand the Wave Function
The wave function for the 2s orbital is given as:
\[ \psi_{2s} = \frac{1}{4\sqrt{2\pi}} Z^{3/2} (2 - Zr)e^{-\frac{Zr}{2}} \]
For nodal surfaces, the wave function must equal zero.
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