When a certain metal was irradiated with light of frequency `3.2 xx 10^(16)s^(-1)` the photoelectrons emitted had three twice the KE as did photoelectrons emitted when the same metal was irradited with light of frequency`2.0 xx 10^(16)s^(-1)` .Calculate the thereshold frequency of the metal

Explanation

To solve the problem step by step, we will use the photoelectric effect equation and the information provided in the question.

### Step 1: Understand the Photoelectric Equation
The photoelectric effect is described by the equation:
\[ KE = h\nu - h\nu_0 \]
Where:
- \( KE \) is the kinetic energy of the emitted photoelectrons,
- \( h \) is Planck's constant,
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