What accelerating potential is needed to product as electron beat with on effecive wavelength of `0.090 Å`

Explanation

To find the accelerating potential needed to produce an electron beam with an effective wavelength of \(0.090 \, \text{Å}\), we can follow these steps:

### Step 1: Convert Wavelength to Meters
The given wavelength is in angstroms, so we need to convert it to meters:
\[ \lambda = 0.090 \, \text{Å} = 0.090 \times 10^{-10} \, \text{m} = 9.0 \times 10^{-12} \, \text{m} \]

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