`1.0 g` of `Mg "atom" ("atomic mass" = 24.0 "amu")` in the vapour phase absorbs `50.0 kJ` energy .Find the composition of the ions if the first and the second IE of Mg are `740 kJ and 1450 "mol^(-1)` respectively

Explanation

To solve the problem step by step, we will follow the outlined process to find the composition of the ions formed when 1.0 g of magnesium absorbs 50.0 kJ of energy.

### Step 1: Calculate the number of moles of magnesium (Mg).
The number of moles can be calculated using the formula:
\[ \text{Number of moles} = \frac{\text{Given mass}}{\text{Molar mass}} \]
Given:
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