The second ionization potential of Be is `17.98 eV` if the electron in Be is assumed to move in a spherical orbit with a central field of effective nuclear charge `(Z_(eff))` consisting of the nucleus and other electron by haw many units of charge in the nucleus shielded by other electrons? (the energy of electrons in first Bohr of H is `-13.6 eV)` If the extent of shielding by the if electron of Li atom is the same as you have calculated above , find the ionization potential of Li

Explanation

To solve the problem step by step, we will break down the information provided and apply the relevant formulas.

### Step 1: Understanding the Problem
We are given the second ionization potential of Beryllium (Be) as 17.98 eV. We need to find the effective nuclear charge (Z_eff) and the extent of shielding (σ) by other electrons. We will then use this information to calculate the ionization potential of Lithium (Li).

### Step 2: Calculate Effective Nuclear Charge (Z_eff) for Be
The formula for the ionization potential (IP) in terms of effective nuclear charge is given by:
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