What is the wavelength of the radiation emitted when the electron in a hydrogen atom jumps from `n = to n = 2`?

Answer

A, B, D

Explanation

`Delta E= 2.179 xx 10^(-18)((1)/(n_(2)^(2)) - (1)/(n_(2)^(2)))`
`= 2.179 xx 10^(-18) ((1)/(4) - (1)/(9))`
`= 0.3026 xx 10^(-18)`
`Delta E = hv = h(c )/(lambda) = hc bar v`
`bar v =Delta E //hc`
` = 0.3026 xx 10^(-18) (J) 6.62 xx 10^(-34) (Js) xx 3 xx 10^(8)(m s^(-1)) = 0.1521 xx 10^(8)(m^(-1))`
Frequency `(v) = c bar v = 3 xx 10^(8) xx 0.01521 xx 10^(8) = 4.56 xx 10^(14) s^(-1)`