Show that the wavelength of a `150 g ` rubber at a velocity of `50 m s^(-1)` is short enough to be determine

Answer

A, B, C, D

Explanation

`lambda = (h)/(mv) = (6.62 xx 10^(-34) J s)/(150 xx 50 m s^(-1)) [ :' J = kg m^(2)s^(-1)]`
`= (6.62 xx 10^(-34) kg m^(2) s^(-1))/(150 xx10^(-3)Kgxx50ms^(-1) 50 m s^(-1))`
`8.8266 xx 10^(35) m`