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Werner Heisenberg considered the limits of how precisely we can measure the properties of an electron or other microscopic particle. He determined that there is a fundamental limit to how closely we can measure both position and momentum. The more accurately we measure the momentum of a particle, the less accurately we can determine its position. The converse also true. This is summed up in what we now call the Heisenberg uncertainty principle.
The equation si `deltax.delta (mv)ge(h)/(4pi)`
The uncertainty in the position or in the momentum of a marcroscopic object like a baseball is too small to observe. However, the mass of microscopic object such as an electon is small enough for the uncertainty to be relatively large and significant.
If the uncertainty in velocity and position is same, then the uncertainty in momentum will be :

A

`8 xx 10^(12) m s^(-1)`

B

`6 xx 10^(12) m s^(-1)`

C

`84xx 10^(12) m s^(-1)`

D

`2 xx 10^(12) m s^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
A

`Delta x Delta p ge (h)/(4pi) rArr Delta p ge sqrt((h)/(4pi)){:' Delta x = Delta p (given)]`
`rArr Delta x ge (1)/(m) sqrt((h)/(4pi)) = 8 xx 10^(12) ms^(-1)[:' Delta p = m Delta v]`
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Werner Heisenberg considered the limits of how precisely we can measure the properties of an electron or other microscopic particle. He determined that there is a fundamental limit to how closely we can measure both position and momentum. The more accurately we measure the momentum of a particle, the less accurately we can determine its position. The converse also true. This is summed up in what we now call the Heisenberg uncertainty principle. The equation si deltax.delta (mv)ge(h)/(4pi) The uncertainty in the position or in the momentum of a marcroscopic object like a baseball is too small to observe. However, the mass of microscopic object such as an electon is small enough for the uncertainty to be relatively large and significant. If the uncertainties in position and momentum are equal, the uncertainty in the velocity is :

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