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The energy of an electron in the first B...

The energy of an electron in the first Bohr orbit of H atom is `-13.6 eV` The potential energy value (s) of exxcited state(s) for the electron in the Bohr orbit of hydrogen is//are

A

`- 3.4 eV`

B

`4.2 eV`

C

`-6.8 eV`

D

`+ 6.8 eV`

Text Solution

Verified by Experts

The correct Answer is:
A
Eecited state is given as `= (-13.6 eV)/(n^(2))`
`e.g. n = 2 ,E = (-13.6)/(4) = - 13.6 eV`
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