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Magnetic moment of V(Z = 23),Cr(Z = 24)...

Magnetic moment of `V(Z = 23),Cr(Z = 24),and Mn(Z= 25) are x,y,z `repectively hence

A

`x= y= z`

B

`x lt y lt z`

C

`x lt zlt y`

D

`z lt y lt x`

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The correct Answer is:
To determine the magnetic moments of Vanadium (V), Chromium (Cr), and Manganese (Mn), we will follow these steps: ### Step 1: Identify the Atomic Numbers and Electronic Configurations - **Vanadium (V)** has an atomic number of 23. Its electronic configuration is: \[ \text{V: } [Ar] 3d^3 4s^2 \] - **Chromium (Cr)** has an atomic number of 24. Its electronic configuration is: \[ \text{Cr: } [Ar] 3d^5 4s^1 \] - **Manganese (Mn)** has an atomic number of 25. Its electronic configuration is: \[ \text{Mn: } [Ar] 3d^5 4s^2 \] ### Step 2: Determine the Number of Unpaired Electrons - For **Vanadium (V)**: - The 3d subshell has 3 electrons (3 unpaired electrons). - The 4s subshell has 2 electrons (paired). - **Total unpaired electrons (n)** = 3. - For **Chromium (Cr)**: - The 3d subshell has 5 electrons (5 unpaired electrons). - The 4s subshell has 1 electron (1 unpaired). - **Total unpaired electrons (n)** = 5 + 1 = 6. - For **Manganese (Mn)**: - The 3d subshell has 5 electrons (5 unpaired electrons). - The 4s subshell has 2 electrons (paired). - **Total unpaired electrons (n)** = 5. ### Step 3: Calculate the Magnetic Moment The magnetic moment (μ) can be calculated using the formula: \[ \mu = \sqrt{n(n + 2)} \] - For **Vanadium (V)**: \[ \mu_V = \sqrt{3(3 + 2)} = \sqrt{3 \times 5} = \sqrt{15} \] - For **Chromium (Cr)**: \[ \mu_{Cr} = \sqrt{6(6 + 2)} = \sqrt{6 \times 8} = \sqrt{48} \] - For **Manganese (Mn)**: \[ \mu_{Mn} = \sqrt{5(5 + 2)} = \sqrt{5 \times 7} = \sqrt{35} \] ### Step 4: Compare the Magnetic Moments Now we compare the values of the magnetic moments: - \( \mu_V = \sqrt{15} \) - \( \mu_{Cr} = \sqrt{48} \) - \( \mu_{Mn} = \sqrt{35} \) Since \( \sqrt{48} > \sqrt{35} > \sqrt{15} \), we can conclude: - \( y > z > x \) - Therefore, the order of magnetic moments is: - \( y > z > x \) ### Final Answer Thus, the magnetic moments of Vanadium, Chromium, and Manganese are in the order: \[ y > z > x \]

To determine the magnetic moments of Vanadium (V), Chromium (Cr), and Manganese (Mn), we will follow these steps: ### Step 1: Identify the Atomic Numbers and Electronic Configurations - **Vanadium (V)** has an atomic number of 23. Its electronic configuration is: \[ \text{V: } [Ar] 3d^3 4s^2 \] - **Chromium (Cr)** has an atomic number of 24. Its electronic configuration is: ...
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CENGAGE CHEMISTRY ENGLISH-ATOMIC STRUCTURE-Exercises Multiple Correct
  1. Which of the following statement about quantum number is correct ?

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  2. A hydrogen like atom in ground st6ate abserbs n photon having the s...

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  3. Magnetic moment of V(Z = 23),Cr(Z = 24),and Mn(Z= 25) are x,y,z repec...

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  4. Consider the ground state Cr atom (Z = 24) The number of electron wi...

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  5. When an electron makes a transition from (n + 1) state to n state ...

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  6. In a sample of H atom , make transition from n = 5 to n = 1 If all ...

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  7. Rutherford's alpha scattering led to which of the following conclusio...

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  8. The probability of finding the electron in p(x) orbit is :

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  9. Which of the following statement concerning Bohr's model is //are tr...

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  10. Which sets of quantum number are consitent with the theory ?

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  11. An electron is not deflected an through a certain region because

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  12. Heisenberg uncertainty principle is not valid for :

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  13. Which of the following statements are correct for an electron that ha...

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  14. The wave charaters of electron was experimenally verified by ………..

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  15. Which of the following statement is //are correct ?

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  16. Which of the following statement is//are correct ?

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  17. The charge cloud of a single electron in a 2p atomic orbital has two ...

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  18. Which of the following statement is/are correct ?

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  19. Which is correct statement in case of Hand's rule ?

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  20. Which of the following is true ?

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