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In a sample of H atom , make transition...

In a sample of H atom , make transition from `n = 5 to n = 1 ` If all the spectral lines are observed , then the line having the third highest energy will corresponding to

A

`5 rarr 3`

B

`4 rarr 1`

C

`3 rarr 1`

D

`5 rarr 4`

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To solve the problem of determining which transition corresponds to the third highest energy when a hydrogen atom transitions from \( n = 5 \) to \( n = 1 \), we will follow these steps: ### Step 1: Identify Possible Transitions When an electron in a hydrogen atom transitions from a higher energy level to a lower one, it emits energy in the form of light. The possible transitions from \( n = 5 \) to lower energy levels are: - \( n = 5 \) to \( n = 4 \) - \( n = 5 \) to \( n = 3 \) - \( n = 5 \) to \( n = 2 \) - \( n = 5 \) to \( n = 1 \) - \( n = 4 \) to \( n = 3 \) - \( n = 4 \) to \( n = 2 \) - \( n = 4 \) to \( n = 1 \) - \( n = 3 \) to \( n = 2 \) - \( n = 3 \) to \( n = 1 \) - \( n = 2 \) to \( n = 1 \) ### Step 2: Calculate Energy Levels The energy of each level can be calculated using the formula: \[ E_n = -\frac{13.6 \, \text{eV}}{n^2} \] Calculating the energies for \( n = 1, 2, 3, 4, 5 \): - \( E_1 = -13.6 \, \text{eV} \) - \( E_2 = -3.4 \, \text{eV} \) - \( E_3 = -1.51 \, \text{eV} \) - \( E_4 = -0.85 \, \text{eV} \) - \( E_5 = -0.54 \, \text{eV} \) ### Step 3: Calculate Energy Differences for Each Transition Now we will calculate the energy differences for each transition: 1. \( n = 5 \) to \( n = 1 \): \[ E = E_1 - E_5 = (-13.6) - (-0.54) = -13.06 \, \text{eV} \] 2. \( n = 5 \) to \( n = 2 \): \[ E = E_2 - E_5 = (-3.4) - (-0.54) = -2.86 \, \text{eV} \] 3. \( n = 5 \) to \( n = 3 \): \[ E = E_3 - E_5 = (-1.51) - (-0.54) = -0.97 \, \text{eV} \] 4. \( n = 4 \) to \( n = 1 \): \[ E = E_1 - E_4 = (-13.6) - (-0.85) = -12.75 \, \text{eV} \] 5. \( n = 4 \) to \( n = 2 \): \[ E = E_2 - E_4 = (-3.4) - (-0.85) = -2.55 \, \text{eV} \] 6. \( n = 4 \) to \( n = 3 \): \[ E = E_3 - E_4 = (-1.51) - (-0.85) = -0.66 \, \text{eV} \] 7. \( n = 3 \) to \( n = 1 \): \[ E = E_1 - E_3 = (-13.6) - (-1.51) = -12.09 \, \text{eV} \] 8. \( n = 3 \) to \( n = 2 \): \[ E = E_2 - E_3 = (-3.4) - (-1.51) = -1.89 \, \text{eV} \] 9. \( n = 2 \) to \( n = 1 \): \[ E = E_1 - E_2 = (-13.6) - (-3.4) = -10.2 \, \text{eV} \] ### Step 4: Rank the Energy Differences Now we will rank the energy differences from highest to lowest: 1. \( n = 5 \) to \( n = 1 \): \( 13.06 \, \text{eV} \) 2. \( n = 4 \) to \( n = 1 \): \( 12.75 \, \text{eV} \) 3. \( n = 3 \) to \( n = 1 \): \( 12.09 \, \text{eV} \) 4. \( n = 5 \) to \( n = 2 \): \( 2.86 \, \text{eV} \) 5. \( n = 4 \) to \( n = 2 \): \( 2.55 \, \text{eV} \) 6. \( n = 3 \) to \( n = 2 \): \( 1.89 \, \text{eV} \) 7. \( n = 5 \) to \( n = 3 \): \( 0.97 \, \text{eV} \) 8. \( n = 4 \) to \( n = 3 \): \( 0.66 \, \text{eV} \) 9. \( n = 2 \) to \( n = 1 \): \( 10.2 \, \text{eV} \) ### Conclusion The transition with the third highest energy corresponds to \( n = 3 \) to \( n = 1 \).

To solve the problem of determining which transition corresponds to the third highest energy when a hydrogen atom transitions from \( n = 5 \) to \( n = 1 \), we will follow these steps: ### Step 1: Identify Possible Transitions When an electron in a hydrogen atom transitions from a higher energy level to a lower one, it emits energy in the form of light. The possible transitions from \( n = 5 \) to lower energy levels are: - \( n = 5 \) to \( n = 4 \) - \( n = 5 \) to \( n = 3 \) - \( n = 5 \) to \( n = 2 \) - \( n = 5 \) to \( n = 1 \) ...
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