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If the threshold wavelength (lambda(0)) ...

If the threshold wavelength `(lambda_(0))` for ejection of electron from metal is `350 nm `then work function for the photoelectric emission is

A

(1) `1.2 xx 10^(-18) J`

B

(2) `1.2 xx 10^(-20) J`

C

(3) `6 xx 10^(-19) J`

D

(4) `6 xx 10^(-12) J`

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The correct Answer is:
To find the work function for photoelectric emission given the threshold wavelength, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Relationship**: The work function (Φ) is related to the frequency (ν) of the emitted electrons by the equation: \[ \Phi = h \nu \] where \( h \) is Planck's constant. 2. **Relate Frequency to Wavelength**: The frequency can be expressed in terms of the wavelength (λ) using the equation: \[ \nu = \frac{c}{\lambda} \] where \( c \) is the speed of light. 3. **Substitute Frequency into Work Function Equation**: We can substitute the expression for frequency into the work function equation: \[ \Phi = h \frac{c}{\lambda} \] 4. **Insert Known Values**: - Planck's constant \( h = 6.626 \times 10^{-34} \, \text{J s} \) - Speed of light \( c = 3.0 \times 10^{8} \, \text{m/s} \) - Threshold wavelength \( \lambda = 350 \, \text{nm} = 350 \times 10^{-9} \, \text{m} \) 5. **Calculate Work Function**: \[ \Phi = 6.626 \times 10^{-34} \, \text{J s} \times \frac{3.0 \times 10^{8} \, \text{m/s}}{350 \times 10^{-9} \, \text{m}} \] 6. **Perform the Calculation**: - First, calculate \( \frac{3.0 \times 10^{8}}{350 \times 10^{-9}} \): \[ \frac{3.0 \times 10^{8}}{350 \times 10^{-9}} = \frac{3.0}{350} \times 10^{8 + 9} = 8.57 \times 10^{15} \, \text{s}^{-1} \] - Now multiply by Planck's constant: \[ \Phi = 6.626 \times 10^{-34} \times 8.57 \times 10^{15} = 5.68 \times 10^{-18} \, \text{J} \] 7. **Convert to Scientific Notation**: The value \( 5.68 \times 10^{-18} \, \text{J} \) can be rounded to \( 6.0 \times 10^{-19} \, \text{J} \). 8. **Select the Correct Option**: The closest option available is \( 6 \times 10^{-19} \, \text{J} \). ### Final Answer: The work function for the photoelectric emission is \( 6 \times 10^{-19} \, \text{J} \). ---

To find the work function for photoelectric emission given the threshold wavelength, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Relationship**: The work function (Φ) is related to the frequency (ν) of the emitted electrons by the equation: \[ \Phi = h \nu \] ...
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