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The ratio of kinetic energy to the total...

The ratio of kinetic energy to the total energy of an electron in a Bohr orbit of the hydrogen atom, is

A

`1//2`

B

`-1//2`

C

`1`

D

`-1`

Text Solution

Verified by Experts

The correct Answer is:
B

`[{:(PE= - (Ze^(2))/(r_(n))","KE = (1)/(2)(Ze^(2))/(r_(n))),(E_(Total) = (-Ze^(2))/(r_(n)) + (1)/(2)(Ze^(2))/(r_(n)) = (-Ze^(2))/(r_(n))),(E_(Total) = (1)/(2) PE),(KE = - (1)/(2)PE):}]`
`(KE)/(PE) = (1)/(2)(Ze^(2))/(r_(n))//(-Ze^(2))/(2r_(n)) = - (1)/(2)`
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