The energy of an electron in the first Bohr orbit of H atom is `-13.6 eV` The potential energy value (s) of exxcited state(s) for the electron in the Bohr orbit of hydrogen is//are

Options

A. `-3.4 eV`
B. `-6.8 eV`
C. `-1.7 eV`
D. `13.6 eV`

Answer

A

Explanation

`E_(n)` "for" `H_(2)^(o+) = (E_(1) for H xx Z^(2))/(n^(2))`
`E_(1) = - 13.6 eV`
The possible excited state value are
`E_(2) = (-13.6)/(4) = - 3.4 eV`
`E_(3) = (-13.6)/(9) = - 1.5 eV`
`E_(4) = (-13.6)/(16) = - 0.85 eV`
So, the value is only `-3.4 eV`