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Assertion (A) : A spectral line will be ...

Assertion (A) : A spectral line will be seen for `2p,-2p` transition
Reason (R ) : Energy is raleased in the form of wave of light when the electron drops from `2p_(x)` , to `2p_(y)` orbital.

A

If both (A) and (R ) correct and (R ) is the correct explanation for (A)

B

If both (A) and (R ) correct and (R ) is the correct explanation for (A)

C

If (A) is correct but (R ) is incorrect

D

If both (A) and (R ) are incorrect

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To solve the question, we need to analyze both the assertion and the reason provided. ### Step 1: Analyze the Assertion The assertion states that a spectral line will be seen for a `2p` to `-2p` transition. In atomic physics, spectral lines are produced when electrons transition between different energy levels. - The `2p` orbitals (2px, 2py, 2pz) are degenerate, meaning they have the same energy level. - A transition between these orbitals (like from `2px` to `2py`) does not involve a change in energy because they are at the same energy level. ...
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Assertion (A) : A spectral line will be seen for 2p_(x) - 2p_(y) transition Reason (R ) : Energy is raleased in the form of wave of light when the electron drops from 2p_(x) , to 2p_(y) orbital.

Assertion (A) : A spectral line will be seen for 2p_(x) - 2p_(y) transition Reason (R ) : Energy is released in the form of wave of light when the electron drops from 2p_(x) , to 2p_(y) orbital.

Spectral line would not ne seen for a 2p_x - 2p_z transition p-orbitals are degenerate orbitals.

STATEMENT-1 : A spectral lne will not be seen for a 2p_(x)-2p_(y) transition. and STATEMENT-2 : Only Balmer lines are observed in the visible region.

The energy of an electron of 2p_(1) orbital is

The energy of an electron of 2p_(x) orbital is :

Draw the shapes of 1s, 2s, 2p_x, 2p_y, and 2p_z, orbitals.

Assertion (A) : The ionisation energy of N is more than that of O Reason (R ) : Electronic configuration of N is more stable due to half - fillied 2p orbitals

Assertion (A) : P_(4) is more reactive than N_(2) Reason (R) : P-P bonds are relatively weaker than N-=N

Assertion : p-nitroaniline is stronger base than p-toluidine . Reason: The electron withdrawing NO_(2) group in the p-nitroaniline makes it a stronger base .

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