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How many of the following are possible ...

How many of the following are possible
`1p,2s,3p,3f,3d`

A

1

B

2

C

3

D

4

Text Solution

AI Generated Solution

The correct Answer is:
To determine how many of the given subshells are possible, we need to analyze each subshell based on the principal quantum number (n) and the azimuthal quantum number (l). The azimuthal quantum number (l) can take values from 0 to (n-1). Let's analyze each subshell one by one: 1. **1p**: - For 1p, n = 1 and l = 1 (since p corresponds to l = 1). - However, the azimuthal quantum number l must be less than n. Here, l = 1 is not less than n = 1. - Therefore, **1p is not possible**. 2. **2s**: - For 2s, n = 2 and l = 0 (since s corresponds to l = 0). - Here, l = 0 is less than n = 2. - Therefore, **2s is possible**. 3. **3p**: - For 3p, n = 3 and l = 1 (since p corresponds to l = 1). - Here, l = 1 is less than n = 3. - Therefore, **3p is possible**. 4. **3f**: - For 3f, n = 3 and l = 3 (since f corresponds to l = 3). - Here, l = 3 is not less than n = 3. - Therefore, **3f is not possible**. 5. **3d**: - For 3d, n = 3 and l = 2 (since d corresponds to l = 2). - Here, l = 2 is less than n = 3. - Therefore, **3d is possible**. Now, let's summarize the results: - Possible subshells: 2s, 3p, 3d - Not possible subshells: 1p, 3f Thus, the total number of possible subshells is **3** (2s, 3p, and 3d). ### Final Answer: **3 possible subshells.**
To determine how many of the given subshells are possible, we need to analyze each subshell based on the principal quantum number (n) and the azimuthal quantum number (l). The azimuthal quantum number (l) can take values from 0 to (n-1). Let's analyze each subshell one by one: 1. **1p**: - For 1p, n = 1 and l = 1 (since p corresponds to l = 1). - However, the azimuthal quantum number l must be less than n. Here, l = 1 is not less than n = 1. - Therefore, **1p is not possible**. ...
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