A compound of vanadium has a magnetic ...

A compound of vanadium has a magnetic moment of `1.73BM` Work out the electronic configuration of vanadium in the compound

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A, B, C, D

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Paramagnetism is a property due to the presence of unpaired electrons. In case of transition metals, as they contain unpaired electrons in the (n-1) d orbitals , most of the transition metal ions and their compounds are paramagnetic. Para magnetism increases with increases in number of unpaired electrons. Magnetic moment is calculated from 'spin only formula' Vz mu=sqrt(n(n+2)) B.M n="number of unpaired electrons" Similarly the colour of the compounds of transition metals may be attributed to the presence of incomplete (n-1) d sub-shell. When an electron from a lower energy of d-orbitals is excited to a higher energy d-orbital, the energy of excitation corresponds to the frequency of light absorbed. This frequency generally lies in the visible region. The colour observed corresponds to complementary colour of the light observed. The frequency of the light absorbed is determined by the nature of the ligand. Titanium shows magnetic moments of 1.73 BM in its compound. What is the oxidation state of titanium in the compound?

In which compound does vanadium has an oxidation number of +4 ?

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