Using Heisenberg's uncertainty principle, calculate the uncertainty in velocity of an electron if uncertainty in its position is `10^(-11)m` Given, `h =6.6 xx 10^(-14)kg m^2s^(-1), m=9.1 xx 10^(-31)kg`

Answer

A, D

Explanation

`1 xx 10^(10)m`
Hint: `Delta x - Delta p = (h)/(4pi) `
or` Delta x - Delta v = (h)/(4pi) `
`Delta x = (h)/(4pi m Delta v) `
`m_(s) = 9.1 xx 10^(-27) g Delta V = 5.7 xx 10^(3) ms^(-1)`