The Lyman series of the hydrogen spectrum can be represented by the equation `v = 3.2881 xx 10^(15)s^(-1)[(1)/((1)^(2)) - (1)/((n)^(2))] [where n = 2,3,…….)`
Calculate the maximum and minimum frequencies of the lines in this series

Answer

A, B, C, D

Explanation

Lyman frequrncy will be maximum corresponding to the maximum energy transition i.e. `1 rarr oo`
`rArr v_(max) = 3.28 xx 10^(15) [(1)/(1^(2)) - (1)/(oo^(2))] s^(-1) = 3.26 xx 10^(15) s^(-1)`
Note that coreresponding wavelength will be shortest wavelength
And Lyman frequency will be coreresponding to minimum energy transition i.e. `1 rarr 2`
`rArr v_(min) = 3.28 xx 10^(15) [(1)/(1^(2)) - (1)/(2^(2))] s^(-1) = 2.46 xx 10^(15) s^(-1)`
Note that coreresponding wavelength will be longest wavelength.