What will be the volume occupied by 2 gm of hydrogen at 300 K and 4 atmospheric pressure if at 273 k and 1 atmospheric pressure the gas occupies 22.4 L.

Explanation

According to Boyle's Law, `P_(1)V_(1)=P_(2)V_(2)`
If `P_(1)` is `1 "bar"`, `V_(1)` will be `2.27 L`.
If `P_(2)=0.2 "bar"`, then
`V_(2)=(P_(1)V_(1))/(P_(2)) =(1"bar"xx2.27 L)/(0.2 "bar")=11.35 L`
since the balloon bursts at `0.2` bar pressure, the volume of the balloon should be less than `11.35 L`.