Pressure remaining constant, at what temperature the volume of a gas will be double of its volume at `0^@C` ?

Explanation

Let initial volume `V_(1)=V` at `300 K`
Final volume `V_(2)=(V)/(2)` at `T_(2)` temperature
Then according to charles's law,
`(V_(1))/(T_(1))=(V_(2))/(T_(2))`
`:, T_(2)=(V_(2)xxT_(1))/(V_(1))=((V)/(2)xx300)/(V)=150K`
Hence, the final temperature is `150 K`.