A sample of gas has a volume of `V_(1)` litre at temperature `t_(1).^(@)C`. When the temperature of the gas is changed to `t_(2).^(@)C` at constant pressure, then the volume of the gas was found to increase by 10%. The percentage increase in temperature is

Explanation

According to Charles's law
`(V_(1))/(T_(1))=(V_(2))/(T_(2))`
`V_(1)=425.8 cm^(3)`, `V_(2)=?`
`T_(1)=273+57=330 K`
`T_(2)=273+37=310K`
`:. V_(2)=(V_(1)xxT_(2))/(T_(1))=(425.8xx310)/(330)=400cm^(3)`