At what centigrade temperature will the volume of a gas at `0^(@)C` triple itself if the pressure remains constant.

Explanation

Let the volume of the gas at `0^(@)C` be `V mL`
Thus, we have
`V_(1)=V mL`, `V_(2)=2V mL`
`T_(1)=0+273=273 K`, `T_(2)=?`
By applying Charles'law, we get
`(V_(1))/(T_(1))=(V_(2))/(T_(2))`
Subsituting the corresponding values, we have
`(V)/(273)=(2V)/(T_(2))`
`T_(2)=(2Vxx273)/(V)=546 K=546-273=278^(@)C`