2g of hydrogen is sealed in a vessel of volume `0.02m^(3)`and is maintained at 300K. Calculate the pressure in the vessel.

Explanation

Volume of `1.0 mol` of a gas at `SATP(V_(1))=24.8xx10^(-3)m^(-3)`
`{:("Initial conditions(SATP)","Final conditions"),(V_(1)=24.8xx10^(-3)m^(3)m, V_(2)=24.8m^(3)),(P_(1)=1 "bar", P_(2)=?),(T_(1)=298.15 K,T_(2)=596.3 K):}`
According to the gas equation,
`(P_(1)V_(1))/(T_(1))=(P_(2)V_(2))/(T_(2))`
or `P_(2)=(P_(1)V_(1)xxT_(2))/(T_(1)xxV_(2))=(1.0xx24.8xx10^(-3)xx596.3)/(298.15xx24.8)`
`=2xx10^(-3)` bar
`:. P_(2)=2xx10^(-3)`bar