A gas of molecular mass 71 g `mol^(-1)` is enclosed in a vessel at a temperature of `30^@C`. If the pressure exerted by the gas is 1065 mm of Hg, calculate the density of the gas.

Explanation

Here, `P=1.5 atm`, `T=300 K`, `M=84.5 g mol^(-1)`,
`R=0.0821 L atm K^(-1)mol^(-1)`
The realtionship between pressure and density is
`P=(rho RT)/(M)`
or `rho=(PM)/(RT)=(1.5xx84.5)/(0.0821xx300)=5.416 g L^(-1)`