Calculate the volume occupied by `5.0 g` of acetylene gas at `50^(@)C` and `740 mm` pressure.

Explanation

Weight of acetylene `(w)=5.0 g`
Molecular weight of acetylene `(C_(2)H_(6))`,
`M_(C_(2)H_(6))=26.0 g mol^(-1)`
`:.` Moles of acetylene
`n_(C_(2)H_(6))=(w)/(M)=(5.0)/(26.0)=0.192`
`P=740 mm=(740)/(760)atm`
`T=273+50=323 K`
Using the gas equation `PV=nRT`, we get
` :. V=(0.192xx0.082xx323)/(740//760)=5.23 L`
The volume of acetylene gas is `5.23 L`.