What mass of potassium chlorate must be decomposed to produce `2.40 L` of oxygen at `0.82 "bar"` and `300 K`?

Explanation

To find the mass of potassium chlorate (KClO3) that must be decomposed to produce 2.40 L of oxygen (O2) at 0.82 bar and 300 K, we can follow these steps:

### Step 1: Use the Ideal Gas Law
The ideal gas law is given by the equation:
\[ PV = nRT \]
Where:
- \( P \) = pressure (in bar)
- \( V \) = volume (in liters)
...