A gas cylinder contains oxygen gas at `25^@C` and 15.0 atm. If the temperature of the surroundings rises to `42^@C`, what would be the pressure of the gas in the cylinder ?

Explanation

`n=(370)/(32)=11.6 mol`
`V=(nRT)/(P)=(11.6xx0.082xx298)/(30.0 atm)=9.432 L`
The final number of moles
`n=(PV)/(RT)=(1.0atmxx9.43)/(0.082xx348)=0.330 mL`
Final weight of `O_(2)=0.330 molxx32=10.6 g`
Mass of `O_(2)` escaped `=370 g(initial)-10.6 g`
`=359 g`