Calculate the pressure exerted by `10^(23)` gas molecules each of mass `10^(-22) g` in a container of volume 1 litre the rms speed is `10^(5) cm s^(-1)`

Explanation

To calculate the pressure exerted by \(10^{23}\) gas molecules, each with a mass of \(10^{-22}\) g, in a container of volume 1 liter with an rms speed of \(10^{5}\) cm/s, we will use the kinetic gas equation:

\[ PV = \frac{1}{3} n m u_{\text{rms}}^2 \]

Where:
- \(P\) = pressure
...